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26/28: Oops, try again. It looks like you didn't log your whole name to the console.
I am so stuck….Any suggestions?
// On line 2, declare a variable myName and give it your name. var myName = “Jackson” // On line 4, use console.log to print out the myName variable. console.log(“myName”); // On line 7, change the value of myName to be just the first 2 // letters of your name. console.log(“Jackson”.substring(0,2)); // On line 9, use console.log to print out the myName variable. console.log(“myName”);
Answer 53fcf785548c35b5fa00084e
Answer 53fa165b80ff33efb50066f4
0 votes
var myName = “Jackson” console.log(myName) var myName = “Ja” console.log(myName)
Answer 53fc9967548c35eae3002f37
0 votes
var myName =”emmy”; console.log(myName); console.log(“emmy”.substring(0,2)); console.log(myName);
1 comments
Sammie Cheston over 9 years
Thank you
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1 comments
Thank you