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0 points
Submitted by Syed Hamza Nasir
over 9 years

It looks like you didn't log the first 2 letters of your name to the console!

I don’t understand my mistake!

// On line 2, declare a variable myName and give it your name. console.log(myName = “Hamza”); // On line 4, use console.log to print out the myName variable. console.log(myName); // On line 7, change the value of myName to be just the first 2 // letters of your name. console.log(myName = myName.substring(0,2)); // On line 9, use console.log to print out the myName variable. console.log(myName);

It’s keeps telling me to try again because I’m missing 2 letters of my name in the console.

Answer 54504355282ae3a75e00002a

0 votes

Permalink

Doesn’t work…

points
Submitted by Syed Hamza Nasir
over 9 years

Answer 54503fb0282ae3aee2000092

-1 votes

Permalink

Try console.log(“myName”.substring(0,2)); aka take out the = my name and end it at myName

points
Submitted by goodiebag21
over 9 years