Take a look at the program below. We have a void function named favorite_animal() and main() with a few statements inside.

#include <iostream> std::string sea_animal = "manatee"; void favorite_animal(std::string best_animal) { std::string animal = best_animal; std::cout << "Best animal: " << animal << "\n"; } int main() { favorite_animal("jaguar"); std::cout << sea_animal << "\n"; std::cout << animal << "\n"; }

When this program is compiled and executed, sea_animal will print, but animal won’t. Why do you think that’s the case?

Scope is the region of code that can access or view a given element.

  • Variables defined in global scope are accessible throughout the program.
  • Variables defined in a function have local scope and are only accessible inside the function.

sea_animal was defined in global scope at the top of the program, outside of main(). So sea_animal is defined everywhere in the program.

Because animal was only defined within favorite_animal() and not returned, it is not accessible to the rest of the program.



If you run the code, you can print secret_knowledge right in main() without entering the passcode. Yikes!

Only people who enter the correct passcode should have access to that knowledge.

Move secret_knowledge into local scope so that it only prints from the function call when the correct code is entered.


Nice work! Now it’s time to get rid of that error.

Delete the line in main() that prints secret_knowledge directly without doing any math and keep the enter_code(0310);.

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