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Since pointers are used to store the memory address of a variable, we need to obtain this address first. This is done by using the reference operator (&). The syntax for this is:

&variableName;

Consider the following piece of code:

int x = 9; printf("%p", &x);

This will output to the screen the memory address of the variable x. To assign an address to a pointer, the following syntax is used:

pointer = &variableName;

Consider the following example:

int x = 727; // Declare variable x int* ptr = &x; // Declare a pointer to an int variable and assign to it the address of variable x printf("%p\n", &x); // Print the address of x printf("%p\n", ptr); // Print the address pointed to by ptr

The code above declares an integer variable x and an int pointer variable ptr. The pointer is then assigned the memory of the variable x. The last two printf() statements print this address; both lines will output the same hexadecimal number as they both refer to the same address in memory.

The address a pointer contains is not constant. A pointer may be reassigned to a new address so long as type consistency is maintained (e.g., int pointer points to a variable of type int). Consider this example:

int* ptr; // Declare pointer to an integer type int x = 3; // Declare variable x ptr = &x; // Assigns memory address of variable x to the pointer printf("%p\n", ptr); // Prints address of variable x int y = 14; // Declare variable y ptr = &y; // Reassigns the pointer to the memory address of variable y printf("%p\n", ptr); // Prints address of variable y

Instructions

1.

Declare a pointer to a double called dblPtr and assign to it the address of variable g.

2.

Print the address of variable g.

3.

Reassign dblPtr to the address of the variable pi.

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