Oftentimes, we will want to calculate an aggregate for data with certain characteristics.

For instance, we might want to know the mean IMDb ratings for all movies each year. We could calculate each number by a series of queries with different `WHERE`

statements, like so:

SELECT AVG(imdb_rating) FROM movies WHERE year = 1999; SELECT AVG(imdb_rating) FROM movies WHERE year = 2000; SELECT AVG(imdb_rating) FROM movies WHERE year = 2001;

and so on.

Luckily, there’s a better way!

We can use `GROUP BY`

to do this in a single step:

SELECT year, AVG(imdb_rating) FROM movies GROUP BY year ORDER BY year;

`GROUP BY`

is a clause in SQL that is used with aggregate functions. It is used in collaboration with the `SELECT`

statement to arrange identical data into *groups*.

The `GROUP BY`

statement comes after any `WHERE`

statements, but before `ORDER BY`

or `LIMIT`

.

### Instructions

**1.**

In the code editor, type:

SELECT price, COUNT(*) FROM fake_apps GROUP BY price;

Here, our aggregate function is `COUNT()`

and we arranged `price`

into groups.

What do you expect the result to be?

**2.**

In the previous query, add a `WHERE`

clause to count the total number of apps that have been downloaded more than 20,000 times, at each price.

**3.**

Remove the previous query.

Write a new query that calculates the total number of downloads for each category.

Select `category`

and `SUM(downloads)`

.