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can anyone tell me what is wrong with this code
var Junk = [“alex”,”wendle”,25,1987];
console.log(junk);
Answer 504e66bfa8dac900020bc696
1 vote
is your variable Junk capitalized, the case should match the console log
Answer 506abb5abdae90000203b14e
0 votes
use Capital J in console.log as well. Use exact letters.
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