Solution: how to get past PygLatin: Check Yourself Bug

The following code worked for me. I was stuck on this one for quite a while. original = raw_input("please enter a word.") if len(original) > 0: print "%s" % (original) else: print "empty, restart and enter a new word"

It didnt work for me I changed it to this and it still won’t print ‘Welcome to the English to Pig Latin translator!’ if size != 1: return True print original else: return False print ‘Empty’ print ‘Please enter a word’ original = raw_input(‘Enter a word’) size = len(original) even when i took out the welcome to pig latin

so far I’m able to input a word. then it doesn’t finish.

so this is my code:

original = raw_input("please enter a word.")

if len(raw_input) > 0: print origianl else: print “empty, restart and enter a new word”

this is what it’s telling me

Traceback (most recent call last):
  File "python", line 2, in <module>
TypeError: object of type 'builtin_function_or_method' has no len()

I’ve tried it with len(original) as well and it tells me

NameError: name 'origianl' is not defined

when I clearly define it.

I just tried

    original = raw_input("please enter a word.")
if len(origianl) > 0:
    print "%s" % (original)
else:
    print "empty, restart and enter a new word"

still no luck…