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(SOLVED) What is the answer
Here is my code:
var main= function() {
$('.dropdown-toggle'.click(function () {
$('.dropdown-menu').toggle();
});
$('.arrow-next').click(function() {
var currentSlide = $('.active-slide');
var nextSlide = currentSlide.next();
var currentDot = $('.active-dot');
var nextDot = currentDot.next();
var nextSlide = currentSlide.next();
var currentDot = $('.active-dot');
var nextDot = currentDot.next();
if(nextSlide.length == 0) {
nextSlide = $('.slide').first();
}
currentSlide.fadeOut(600).removeClass('active-slide');
nextSlide.fadeIn(600).addClass('active-slide');
currentDot.removeClass('.active-dot');
nextDot.addClass('.active-dot');
});
$(document).ready(main);
it doesn’t work! can someone give me the answer?
Answer 5477828d7c82ca3a630046be
3 votes
sorry here is the answer
var main = function(){
$('.dropdown-toggle').click(function(){
$('.dropdown-menu').toggle();
});
$('.arrow-next').click(function() {
var currentSlide = $('.active-slide');
var nextSlide = currentSlide.next();
var currentDot = $('.active-dot');
var nextDot = currentDot.next();
if(nextSlide.length === 0) {
nextSlide = $('.slide').first();
nextDot = $('.dot').first();
}
currentSlide.fadeOut(600).removeClass('active-slide');
nextSlide.fadeIn(600).addClass('active-slide');
currentDot.removeClass('active-dot');
nextDot.addClass('active-dot');
});
};
$(document).ready(main);
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4 comments
Many Thanks Zafar, My code looked like yours but did not ,work but when i copied and pasted it did the job.
You are absolutely welcome!
Got the same problem, thanks
This didn’t work for me