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what is happening?
this keeps telling me i need to remember to remove the active dot from the current dot.
var main = function() { $(‘.dropdown-toggle’).click(function() { $(‘.dropdown-menu’).toggle(); });
$(‘.arrow-next’).click(function() { var currentSlide = $(‘.active-slide’); var nextSlide = currentSlide.next();
var currentDot = $(‘.active-dot’); var nextDot = currentDot.next();
if(nextSlide.length == 0) { nextSlide = $(‘.slide’).first(); }
currentSlide.fadeOut(600).removeClass(‘active-slide’); nextSlide.fadeIn(600).addClass(‘active-slide’);
currentDot.removeClass(‘active-dot’); nextDot.addClass(‘active-dot’); });
();active-slde)
}
$(document).ready(main);
Answer 55497f10e39efe94c60001c3
@Minion2000, firs of all, remove ();active-slde) from your code…
+++++ flipboard the next && prev steps
s t e p s - - f o r - - n e x t S l i d e -1 -1a create a selection of nextSlide <<done -1b create a selection of nextDot <<done -2 check if selection of nextSlide is EMPTY <<done -2a if EMPTY change nextSlide selection to first slide <<done -2b and change nextDot selection to first Dot << forgotten -3 swap -active-slide- and -active-dot- class from current to next <<done
s t e p s - - f o r - - p r e v S l i d e -1 -1a create a selection of prevSlide -1b create a selection of prevDot -2 check if selection of prevSlide is EMPTY -2a if EMPTY change prevSlide selection to last slide -2b and change prevDot selection to last Dot -3 swap -active-slide- and -active-dot- class from current to prev
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