A dataset of length n can be divided *log n* times until everything is completely divided. Therefore, the search complexity of binary search is O(log n).

A binary search can be performed in an iterative approach. Unlike calling a function within the function in a recursion, this approach uses a loop.

function binSearchIterative(target, array, left, right) {while(left < right) {let mid = (right + left) / 2;if (target < array[mid]) {right = mid;} else if (target > array[mid]) {left = mid;} else {return mid;}}return -1;}

In a recursive binary search, there are two cases for which that is no longer recursive. One case is when the middle is equal to the target. The other case is when the search value is absent in the list.

```
binary_search(sorted_list, left_pointer, right_pointer, target)
if (left_pointer >= right_pointer)
base case 1
mid_val and mid_idx defined here
if (mid_val == target)
base case 2
if (mid_val > target)
recursive call with left pointer
if (mid_val < target)
recursive call with right pointer
```

In a recursive binary search, if the value has not been found then the recursion must continue on the list by updating the left and right pointers after comparing the target value to the middle value.

If the target is less than the middle value, you know the target has to be somewhere on the left, so, the right pointer must be updated with the middle index. The left pointer will remain the same. Otherwise, the left pointer must be updated with the middle index while the right pointer remains the same. The given code block is a part of a function `binarySearchRecursive()`

.

function binarySearchRecursive(array, first, last, target) {let middle = (first + last) / 2;// Base case implementation will be in here.if (target < array[middle]) {return binarySearchRecursive(array, first, middle, target);} else {return binarySearchRecursive(array, middle, last, target);}}

Binary search performs the search for the target within a sorted array. Hence, to run a binary search on a dataset, it must be sorted prior to performing it.

The binary search starts the process by comparing the middle element of a sorted dataset with the target value for a match. If the middle element is equal to the target value, then the algorithm is complete. Otherwise, the half in which the target cannot logically exist is eliminated and the search continues on the remaining half in the same manner.

The decision of discarding one half is achievable since the dataset is sorted.

The binary search algorithm takes time to complete, indicated by its `time complexity`

. The worst-case time complexity is `O(log N)`

. This means that as the number of values in a dataset increases, the performance time of the algorithm (the number of comparisons) increases as a function of the base-2 logarithm of the number of values.

Example: Binary searching a list of 64 elements takes at MOST `log2(64)`

= 6 comparisons to complete.

The binary search algorithm efficiently finds a goal element in a sorted dataset. The algorithm repeatedly compares the goal with the value in the middle of a subset of the dataset. The process begins with the whole dataset; if the goal is smaller than the middle element, the algorithm repeats the process on the smaller (left) half of the dataset. If the goal is larger than the middle element, the algorithm repeats the process on the larger (right) half of the dataset. This continues until the goal is reached or there are no more values.

Binary search can be implemented using recursion by creating a function that takes in the following arguments: a sorted list, a left pointer, a right pointer, and a target.

The base cases must account for when the left and right pointers are equal, as well as when the target is found, in which case the index of the array is returned.

Initially, set the left pointer to index 0 of the list and right pointer to the last index. If middle value > target, right pointer = middle value. If middle value < target, left pointer = middle value. Call the binary search function with the properly adjusted pointers.

def binary_search(sorted_list, left_pointer, right_pointer, target):if left_pointer >= right_pointer:#base case 1#mid_val and mid_idx defined hereif mid_val == target:#base case 2if mid_val > target:#recursive call with left pointerif mid_val < target:#recursive call with right pointer

- Divide-and-conquer solves a large problem by recursively breaking it down into smaller subproblems until they can be solved directly.
- Divide-and-conquer works in three steps: divide, conquer, and combine.
- It is more efficient than brute force approaches.
- It is prone to stack overflow error due to the use of recursion.

The `BinarySearchTree`

Python class has a `.depth_first_traversal()`

instance method that prints the in-order depth-first traversal of the tree. The output will always be in ascending order. It takes no variables and returns nothing.

def depth_first_traversal(self):if (self.left is not None):self.left.depth_first_traversal()print(f'Depth={self.depth}, Value={self.value}')if (self.right is not None):self.right.depth_first_traversal()

The `BinarySearchTree`

Python class has a `.get_node_by_value()`

instance method that takes in a `value`

and returns the corresponding `BinarySearchTree`

node, or `None`

if it doesn’t exist. The method uses recursion to search through the sides of the tree. On an averagely balanced binary search tree with `N`

nodes, the performance would be `O(logN)`

, just like the Binary Search algorithm.

def get_node_by_value(self, value):if (self.value == value):return selfelif ((self.left is not None) and (value < self.value)):return self.left.get_node_by_value(value)elif ((self.right is not None) and (value >= self.value)):return self.right.get_node_by_value(value)else:return None

The `BinarySearchTree`

Python class has an `.insert()`

method that takes in a `value`

and uses recursion to add a new node to the tree while maintaining the binary tree property. The method returns nothing. On an averagely balanced binary search tree with `N`

nodes, the performance would be `O(logN)`

.

def insert(self, value):if (value < self.value):if (self.left is None):self.left = BinarySearchTree(value, self.depth + 1)print(f'Tree node {value} added to the left of {self.value} at depth {self.depth + 1}')else:self.left.insert(value)else:if (self.right is None):self.right = BinarySearchTree(value, self.depth + 1)print(f'Tree node {value} added to the right of {self.value} at depth {self.depth + 1}')else:self.right.insert(value)

The Python implementation of the `BinarySearchTree`

class should contain `value`

and `depth`

instance variables, as well as `left`

and `right`

pointers. The constructor has the following parameters:

`value`

`depth`

, which has a default value of`1`

The `left`

and `right`

pointers are set to `None`

in the constructor.

def __init__(self, value, depth=1):self.value = valueself.depth = depthself.left = Noneself.right = None