# modf()

Published Dec 13, 2022
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The `modf()` function splits a given number into an integral and a fractional part.

## Syntax

``````modf(number, integralPart)
``````

The `modf()` function takes two parameters:

• `number`, a floating point value (`double`, `float` or `long double`) to split into integral and fractional parts.
• `integralPart`, a pointer to `number` that stores the integral part. It will have the same type and sign as `number`.

The `modf()` function returns the fractional part of `number` with the same sign as `number`.

## Example

This example uses the `modf()` function to return the fractional part of `6.02214`:

```#include <iostream>#include <cmath>
int main() {  double num1 = 6.02214;  double intPart;  double fractPart;
fractPart = modf(num1, &intPart);
std::cout << num1 << " = " << intPart << " + " << fractPart << "\n";
return 0;}
```

This example results in the following output:

```6.02214 = 6 + 0.02214
```

## Codebyte Example

This example uses the `modf()` function to take an argument of `1.602176634` and return its fractional part while also storing the value of the integral part of the argument into `integral`:

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