# Hypot()

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Anonymous contributor
Published Aug 22, 2023
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The Hypot() function returns the square root of the sum of two squares. In other words, the method returns the result of the following formula:

$hypotenuse = \sqrt{(x * x) + (y * y)}$

## Syntax

import math

result := math.Hypot(x, y)


Hypot() accepts two arguments (x , y) of type float64 and returns a value of type float64.

Note:

• If either argument is negative, or both, the result is positive.
• If either argument is positive infinity (+Inf), the result will be positive infinity.
• If 0 is passed as both arguments, the result is 0. If one of the arguments is 0 the result is equal to the other argument.
• If either argument passed is NaN, the result will be NaN.

## Example

package main
import("fmt"      "math")
func main() {  fmt.Printf("Hypotenuse of 3 and 4 = %f\n", math.Hypot(3 , 4))  fmt.Printf("Hypotenuse of -1.5 and -1.5 = %f\n", math.Hypot(-1.5,-1.5))
}


The above example results in the following output:

Hypotenuse of 3 and 4 = 5.000000Hypotenuse of -1.5 and -1.5 = 2.121320


## Codebyte Example

The runnable example of the Hypot() function of the cases where 0 or a negative number is at least one of the arguments.

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