# .log1p()

The `Math.log1p()` method returns the natural logarithm of a number plus 1.

## Syntax

``Math.log1p(a);``
• If `a` is a positive number, the return value is a `double`.
• If `a` is `NaN` or less than -1, the return value is `NaN`.
• If `a` is -1, the return value is negative infinity
• If `a` is positive infinity, the return value is positive infinity.
• If `a` is positive or negative zero, the return value is positive or negative zero.

## Example

The following example demonstrates using the `.log1p()` method to find natural logs:

```// Main.javapublic class Main {  public static void main(String args[]) {    double a = 23;    double b = -42;    double c = 0;    double d = -0;
System.out.println("The result of log1p(" + a + ") is: " + Math.log1p(a));    System.out.println("The result of log1p(" + b + ") is: " + Math.log1p(b));    System.out.println("The result of log1p(" + c + ") is: " + Math.log1p(c));    System.out.println("The result of log1p(" + d + ") is: " + Math.log1p(d));  }}```

This will produce the following output:

`The result of log1p(23.0) is: 3.1780538303479458The result of log1p(-42.0) is: NaNThe result of log1p(0.0) is: 0.0The result of log1p(0.0) is: 0.0`

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