.parse()
Published Jun 2, 2022
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The .parse()
method returns a new value taken from a provided JSON string.
Syntax
JSON.parse(jsonString, transformer);
The jsonString
must contain valid JSON. Otherwise, a SyntaxError
is thrown. Common JSON includes single objects or arrays of them. However, data types like booleans and numbers are also valid.
The transformer
function is an optional parameter that operates directly on the parsed jsonString
before the resulting transformation is returned.
Example
In the example below, a valid JSON object is stored in a variable, myJSONString
, and then passed into the .parse()
method as an argument:
let myJSONString = '{"Hello": "World"}';console.log(JSON.parse(myJSONString));
The output will look like this:
{ Hello: 'World' }
Codebyte Example
The following example further demonstrates how the .parse()
method works:
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